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View Full Version : Stableford scoring for Joe Who Invitational


Feb 02 2005, 12:01 PM
- More than 1 over par (or no score returned) -1 points
- One over par - 0 points
- Par - 1 points
- One under par - 2 points
- Two under par - 3 points

I saw the above scoring system for the upcoming Joe Who monthly, and I really don't get it. The point values that were chosen seem to defeat the purpose because, barring any double-bogeys or worse, the outcome will be exactly the same as with regular scoring. The modified Stableford scoring used for "The International" (the so-called "5th major" on the PGA tour) is set to reward aggressive play by making a birdie help you (+2 points) more than a bogey hurts you(-1 point), with pars worth no points.

I don't really care, since I can't be there anyway, but just thought I would raise the point.

ActiveCurrent
Feb 02 2005, 12:40 PM
Maybe I should have asked the Tournament Director before I posted those points...? Sorry, maybe it is wrong. Hey Joe/Neil, is that right?

Feb 02 2005, 12:45 PM
Kevin,

You're not necessarily wrong. Traditional Stableford scoring is almost identical to what you've posted, and will also have the same outcome as stroke play. I'm just not sure that this is what you want. My suggestion would be ace +5, birdie +2, par 0, bogey -1, double bogey or worse -3., or something similar.

Feb 02 2005, 12:55 PM
Kevin,

You're not necessarily wrong...traditional Stableford scoring is very similar to what you have posted, and normally gives the exact same outcome as in stroke play. I thought that you might want to use some sort of modified system (ace +5, birdie +2, par 0, bogey -1, double bogey or worse -3, or something similar), to give a different result than stroke play.

myze13325
Feb 02 2005, 02:08 PM
I don't agree the scoring would be the same,

if I get 10 birds = 20Pts
6 pars = 6 Pts
2 bogeys = -2

24 pts or -8

if i get 8 birdies (16Pts)
10 pars (10pts)

Then I have -8 or 26 pts

Same score, more birdes win!

I say we use:

1=5
2=3
3=1
4 or more = 0

Feb 02 2005, 07:27 PM
Neil,

The 2 bogeys would be 0 points, not -2, so either way would be 8-under-par and 26 points.

jaxx
Feb 02 2005, 10:57 PM
Stableford scoring system (http://www.myscorecard.com/splash_stblfd.html)

stick
Feb 02 2005, 11:49 PM
How do you play more aggressive at kentwood?

I know I have to lay up on #1 for fear of the road but then again I've got that massive snap... ;)